修复代码生成短字段无法识别问题

ruoyi-generator/src/main/resources/vm/java/domain.java.vm

@@ -51,8 +51,12 @@ public class ${ClassName} extends ${Entity}
 #end
 #foreach ($column in $columns)
 #if(!$table.isSuperColumn($column.javaField))
+    #if($column.javaField.substring(1,2).matches("[A-Z]"))
+        #set($AttrName=$column.javaField)
+    #else
         #set($AttrName=$column.javaField.substring(0,1).toUpperCase() + ${column.javaField.substring(1)})
-    public void set${AttrName}($column.javaType $column.javaField) 
+    #end
+public void set${AttrName}($column.javaType $column.javaField)
     {
         this.$column.javaField = $column.javaField;
     }
@@ -68,8 +72,13 @@ public class ${ClassName} extends ${Entity}
     public String toString() {
         return new ToStringBuilder(this,ToStringStyle.MULTI_LINE_STYLE)
 #foreach ($column in $columns)
-#set($AttrName=$column.javaField.substring(0,1).toUpperCase() + ${column.javaField.substring(1)})
-            .append("${column.javaField}", get${AttrName}())
+    #if($column.javaField.substring(1,2).matches("[A-Z]"))
+        #set($AttrName=$column.javaField)
+    #else
+        #set($AttrName=$column.javaField.substring(0,1).toUpperCase() + ${column.javaField.substring(1)})
+    #end
+
+        .append("${column.javaField}", get${AttrName}())
 #end
             .toString();
     }